Data communication and networks: A transport layer message consisting of 1500 bits of data and 160 bits of header is sent to an internet layer, which appends another 160 bits of header. This is the transmitted through two networks, each of which uses a 24-bit packet header. The destination network has a max packet size 800 bits. How many bits, including headers, are delivered to the network-layer protocol at the destination? Stan
i don't know anything about computers, but my guess is 1868 the only thing i know about data communication and networks is that my DSL line is better than 56k
Ask ken i think he took that in University. He'd know anyways he's a brain when it comes to computers!
Thank me later: To the Network Layer, packets from the IP layer are considered as data, we call it IP data. IP data = User Data + Transport Header + IP Header = 1500 + 160 + 160 bits = 1820 bits The maximum packet size for the network is 800 bits and network header is 24 bits. So the maximum data size the network can handle is (800 – 24) = 776. Since we have 1820 bits to be delivered, it is too large to fix in one packet. So fragmentation is needed. Define n = number of fragments d = total number of data to be transmitted at the network layer = IP data = 1820 m = maximum data size for the network = 776 n= [ d/m] = [1820/776] = [2.3] = 3 Define t = total number of delivered to the destination h = total overhead = network header x n = 24 x 3 = 72 t = h + d = 72 + 1820 = 1892
